台历模板2021电子版打印虎年台历模板 _生活百科

2011台历模板各位宝妈有没有2011台历模板发给我？2011台现在做还早呢。宝树的个性定制里有。

文章插图
有没有台历模板里放多张照片的啊？有没有台历模板里放多张照片的啊第二行第二列就是一个可以放多张照片的模板哦!亲可以试试
程序设计编写一万年历系统）#include
#define YEAR 365
int leap(int year)
int n;
n=(year%4==0&&year%4!=0||year%400==0);
return(n);
void count(int year, int month) /*基：2000年1月*/
int i,day,first_day,flag,year1,year2,temp=6;
flag=leap(year);
year1=year/100; /*相差几百年*/
year2=year%100; /*中间几十年*/
if(year>=2000) /*大于2000年*/
year1-=20;
day=year1/4; /*百闰年数*/
day+=(YEAR+24)*year1+YEAR*year2+(year2-1)/4; /*2000年至现年总天数*/
if(year>2000)day++; /*加上2000年闰年2月的29天*/
switch(month)
case 1:day+=0;break;
case 2:day+=31;break; /*加上月份天数*/
case 3:day+=59+flag;break;
case 4:day+=90+flag;break;
case 5:day+=120+flag;break;
case 6:day+=151+flag;break;
case 7:day+=181+flag;break;
case 8:day+=212+flag;break;
case 9:day+=243+flag;break;
case 10:day+=273+flag;break;
case 11:day+=304+flag;break;
case 12:day+=334+flag;break;
day+=temp; /*加上2000年1月1号是星期六*/
first_day=day%7; /*对7取余，为1号星期*/
else /*以下25行，计算<2000年，算法同上*/
year1=20-1-year1;
year2=100-year2-1; /*倒减，应多减1*/
day=year1/4;
day+=36524*year1+365*year2+year2/4;
switch(month)
case 12:day+=31;break;
case 11:day+=61;break;
case 10:day+=92;break;
case 9:day+=122;break;
case 8:day+=153;break;
case 7:day+=184;break;
case 6:day+=214;break;
case 5:day+=245;break;
case 4:day+=275;break;
case 3:day+=306;break;
case 2:day+=334+flag;break;
case 1:day+=365+flag;break;
day-=temp; /*减去1号的6天*/
day=day%7;
first_day=(7-day)%7; /*反对称*/
switch(month)
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:month=31;break;
case 4:
case 6:
case 9:
case 11:month=30;break;
case 2:month=28+flag;
printf(" SUN MON TUE WED THU FRI SAT\n");
for(i=1;i<=4*first_day;i++) /*输出空格*/
printf(" ");
for(i=0;i<month;i++)
printf("%4d",i+1); /*输出日历*/
if((first_day+i)%7==6)printf("\n");
printf("\n");
void main()
int year,i;
printf("please input year :\n");
while(scanf("%d",&year)!=1)
printf("输入错误，请重新输入");
fflush(stdin);
for(i=1;i<13;i++)
printf("month:%d\n",i);
count(year,i);
getch();
我们上一星期课程设计也是这个题朋友你那是在折腾人哦~~~谁也没心思编写那个程序啊有点无聊的感觉您好：
很高兴回答你的问题，希望对你有用！
#ifndef _CALENDAR_H
#define _CALENDAR_H
#include
struct myDATE{
int year;
int month;
int day;
bool isRunYue;
class calendar{
public:
calendar(){};
~calendar(){};
LONG lDaysFrom1900(myDATE date);//date与1900年相差的天数
UINT lYearDays(UINT y);//农历y年的总天数
UINT leapDays(UINT y);//传回农历 y年闰月的天数
UINT leapMonth(UINT y);// 传回农历 y年闰哪个月 1-12 , 没闰传回 0
UINT monthDays(UINT y,UINT m);//传回农历 y年m月的总天数
myDATE Lunar(myDATE date);//输入阳历日期，返回阴历日期
char* dayOfWeek(myDATE date);//输入阳历日期，返回星期几
char* getLunarString (myDATE date );// 输入阴历日期,得到表示农历的字串
UINT solarDays(UINT y,UINT m);//传回国历 y年某m+1月的天数
private:
char m_slunar[100];//用于存储农历信息
static DWORD lunarInfo[];//
static UINT solarmonth[];
static char sSolarTerm[];
static DWORD dTermInfo[];
static char sFtv[];
#endif
#include "calendar.h"
#include
DWORD calendar::lunarInfo[]={
0x04bd8,0x04ae0,0x0a570,0x054d5,0x0d260,0x0d950,0x16554,0x056a0,0x09ad0,0x055d2,
0x04ae0,0x0a5b6,0x0a4d0,0x0d250,0x1d255,0x0b540,0x0d6a0,0x0ada2,0x095b0,0x14977,
0x04970,0x0a4b0,0x0b4b5,0x06a50,0x06d40,0x1ab54,0x02b60,0x09570,0x052f2,0x04970,
0x06566,0x0d4a0,0x0ea50,0x06e95,0x05ad0,0x02b60,0x186e3,0x092e0,0x1c8d7,0x0c950,
0x0d4a0,0x1d8a6,0x0b550,0x056a0,0x1a5b4,0x025d0,0x092d0,0x0d2b2,0x0a950,0x0b557,
0x06ca0,0x0b550,0x15355,0x04da0,0x0a5d0,0x14573,0x052d0,0x0a9a8,0x0e950,0x06aa0,
0x0aea6,0x0ab50,0x04b60,0x0aae4,0x0a570,0x05260,0x0f263,0x0d950,0x05b57,0x056a0,
0x096d0,0x04dd5,0x04ad0,0x0a4d0,0x0d4d4,0x0d250,0x0d558,0x0b540,0x0b5a0,0x195a6,
0x095b0,0x049b0,0x0a974,0x0a4b0,0x0b27a,0x06a50,0x06d40,0x0af46,0x0ab60,0x09570,
0x04af5,0x04970,0x064b0,0x074a3,0x0ea50,0x06b58,0x055c0,0x0ab60,0x096d5,0x092e0,
0x0c960,0x0d954,0x0d4a0,0x0da50,0x07552,0x056a0,0x0abb7,0x025d0,0x092d0,0x0cab5,
0x0a950,0x0b4a0,0x0baa4,0x0ad50,0x055d9,0x04ba0,0x0a5b0,0x15176,0x052b0,0x0a930,
0x07954,0x06aa0,0x0ad50,0x05b52,0x04b60,0x0a6e6,0x0a4e0,0x0d260,0x0ea65,0x0d530,
0x05aa0,0x076a3,0x096d0,0x04bd7,0x04ad0,0x0a4d0,0x1d0b6,0x0d250,0x0d520,0x0dd45,
0x0b5a0,0x056d0,0x055b2,0x049b0,0x0a577,0x0a4b0,0x0aa50,0x1b255,0x06d20,0x0ada0
UINT calendar::solarmonth[]={31,28,31,30,31,30,31,31,30,31,30,31};
UINT calendar::lYearDays(UINT y)
UINT i, sum = 348;
for(i=0x8000; i>0x8; i>>=1)
sum += (lunarInfo[y-1900] & i)? 1: 0;
return(sum+leapDays(y));
UINT calendar::leapDays(UINT y)
if(leapMonth(y))
return (lunarInfo[y-1900] & 0x10000)? 30: 29;
return 0;
UINT calendar::leapMonth(UINT y)
return lunarInfo[y-1900] & 0xf;
UINT calendar::monthDays(UINT y,UINT m)
return (lunarInfo[y-1900] & (0x10000>>m))? 30: 29;
LONG calendar::lDaysFrom1900(myDATE date)
LONG days;
days=365*date.year+(date.year-1)/4-(date.year-1)/100+(date.year-1)/400-
(365*1900+(1900-1)/4-(1900-1)/100+(1900-1)/400);
for(int i=0;i<date.month-1;i++)
days+=solarmonth[i];
days+=date.day;
if((date.year%4==0&&date.year%100!=0)||date.year%400==0)
if(date.month>2)
days++;
return days;
myDATE calendar::Lunar(myDATE date)
LONG offset;
int i, leap=0, temp=0;
myDATE retdate;
offset=lDaysFrom1900(date)-30;
for(i=1900; i0; i++)
temp = lYearDays(i);
offset -= temp;
if(offset<0)
offset += temp;
retdate.year = i;
leap = leapMonth(i);
bool isLeap = false;
for(i=1; i0; i++)
if(leap>0 && i==(leap+1) && isLeap==false)
isLeap = true;
temp = leapDays(retdate.year);
temp = monthDays(retdate.year, i);
if(isLeap==true && i==(leap+1))
isLeap = false;
offset -= temp;
if(offset==0 && leap>0 && i==leap+1)
if(isLeap)
isLeap = false;
isLeap = true;
if(offset<=0)
offset += temp;
retdate.month = i;
retdate.day = offset ;
retdate.isRunYue=isLeap;
return retdate;
char* calendar::getLunarString (myDATE date)
TCHAR szNongli[30], szNongliDay[10],szShuXiang[10];
const char *cTianGan[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; /*天干名称*/
const char *cDiZhi[] = {"子","丑","寅","卯","辰","巳","午", "未","申","酉","戌","亥"}; /*地支名称*/
const char *cShuXiang[] = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"}; /*属相名称*/
const char *cDayName[] = { "*","初一","初二","初三","初四","初五", /*农历日期名*/
"初六","初七","初八","初九","初十",
"十一","十二","十三","十四","十五",
"十六","十七","十八","十九","二十",
"廿一","廿二","廿三","廿四","廿五",
"廿六","廿七","廿八","廿九","三十"};
const char *cMonName[] = {"*","正","二","三","四","五","六", "七","八","九","十","十一","腊"};
/*--生成农历天干、地支、属相 ==> wNongli--*/
int nShuXiang = ((date.year - 4) % 60) % 12;
if ( nShuXiang = sizeof(cShuXiang)/sizeof(cShuXiang[0]) )
return NULL ;
wsprintf(szShuXiang,"%s",cShuXiang[nShuXiang]);
int nTianGan = ((date.year - 4) % 60) % 10;
if ( nTianGan = sizeof(cTianGan)/sizeof(cTianGan[0]) )
return NULL;
int nDiZhi = ((date.year - 4) % 60) % 12;
if ( nDiZhi = sizeof(cDiZhi)/sizeof(cDiZhi[0]) )
return NULL;
wsprintf(szNongli,"%s(%s%s)年",szShuXiang,cTianGan[nTianGan],cDiZhi[nDiZhi]);
/*--生成农历月、日 ==> wNongliDay--*/
if ( date.month = sizeof(cMonName)/sizeof(cMonName[0]) )
return NULL;
if (date.isRunYue)
wsprintf(szNongliDay,"闰%s",cMonName[date.month]);
strcpy(szNongliDay,cMonName[date.month]);
strcat(szNongliDay,"月");
if ( date.day = sizeof(cDayName)/sizeof(cDayName[0]) )
return NULL;
strcat(szNongliDay,cDayName[date.day]);
strcat(szNongli,szNongliDay);
sprintf(m_slunar,szNongli);
return m_slunar;
char* calendar::dayOfWeek(myDATE date)
char *cWeekName[] = {"星期日","星期一","星期二","星期三","星期四","星期五","星期六"};
if(date.month==1||date.month==2)
date.month+=12;
date.year--;
return cWeekName[(date.day+1+2*date.month+3*(date.month+1)/5+date.year+date.year/4-date.year/100+date.year/400)%7];
UINT calendar::solarDays(UINT y,UINT m)
if(m==1)//2月
return(((y%4 == 0) && (y%100 != 0) || (y%400 == 0))? 29: 28);
return(solarmonth[m]);
=================================================

文章插图
万年历阴历转阳历表格5304天前
1998年1月
1998 年 1 月 28 日星期三
【台历模板2021电子版打印虎年台历模板】阴历1998年一月一日是阳历1998年1月 28日水瓶座

台历模板2021电子版打印 虎年台历模板

台历模板2021电子版打印虎年台历模板